Errors in Aug 2010
version of Ruina/Pratap
Help us improve the book: send email to email@example.com
Please suggest improvements. For example, if you have trouble finding something, even if you did eventually find it, we'd like to know. Or, do you think any explanations are weak? Give us some clues about your difficulties learning with this book.
Make money if you are the first to find an error: $1.00 for math errors, $5 for real errors or things that need deep fixing (with suggestion about how to fix). How?: Subject line in email: TEXT ERRORS. Then list like the Known Errors below, (XX are your initials), e.g.,
Sect 13.2, pg 642, paragraph above "More about pendula". -XX 2/5/09
In the argument of the exponentials change gt/l to +- sqrt(g/l)t.
We keep track of typos, case and tense mismatches, mising closing parentheses, spelling and grammatical errors, etc, but don't list them all here. The errors below are more serious.
* = an appropriate
repair has already been made in the source file
! = non-trivial error, readers should note.
! Section 2.1, page 45, 1st equation: -IV 8/25/10
rB/A = -rB/A should be rB/A = -rA/B
! Section 2.3, page 68, item 7: -BE 8/26/10
As written there is a vector minus a scalar. Bad. The second term inside the absolute value sign needs to be multiplied by rB/A / |rB/A|. That is, as written the second term is the length of the projection along the line. That needs to be multiplied by a unit vector along the line to make a vector to subtract from rC/A.
! Section 2.3, page 69, paragraph over the first "Example" -
Change AxB = (A1B2 - B2A1)e3 (As incorrectly printed, the cross product is zero.)
to AxB = (A1B2 - A2B1)e3.
! Section 2.3, Sample 2.19, page 77: -SC 9/13/10
Change A(-1,4) to A(-1,1)
! Section 2.4, pg 88, Moment about an axis example, - SC 9/18/10
Change -17/sqrt(2) mN to -41/sqrt(2) mN
! Problem 2.7.11b, page 146. - EE 9/06/10
The cutout circle is not drawn to scale, it actually encompasses the center of the big circular plate.
! Problem 4.5.10, page 252 -KS 9/8/10
change IE to CE
change I,C and B to C and B
! Pages 285-6, truss matrices setup. -Dan Levine
There are a few errors in the matrix setup which are corrected here.
! Problem 5.2.7, page 314, -JZ 9/17/10
On the figure change the base lengthAF from 2L to 3L.
(as printed, points C and D coincide)
! Problem 5.3.6, page 315, -AR 9/20/10
On the figure there should be rollers at E (and the figure should be bigger).
Sect. 6.3, pg. 357, "Pulley and Chain Drives" bottom
of par. 1. -KL10/08/10
Change "Fig 6.53B" to "Fig 6.55B"
! Problem 6.2.8, page 368 -AR 9/17/10
Delete the problem. The problem is not well enough defined. No simple fix.
Problem 6.3.2, page 371 -SP 10/13/10
dimension of bottom length is \ell (script letter L)
*Problem 6.3.14, page 373 -AR 10/13/10
Figure needs various clarifications.
! Problem 8.1.3, pg 409 (& 1007), Answer -NAS 10/17/10
Change 5.85 x 10^5N to 5.85x10^4N.
! Sample 14.32, page 826. -MC 2007
Here is an extensive correction to this sample by Mike Coleman.
Also v_D should be v_0.
and v_P should be v_G.
First and second figures need A' (not A) on disk.
Section 16.1, Sample 16.8. Some ideas from Les
Do the frictionless case of Sample 16.8 in the text.
Point out that the increase in kinetic energy is the work of the contact force.
In the sample, use a dot product with e_r + mu e_theta to get the equation of motion in one less step. In the sample point out that the work of the constraint force is the change of kinetic energy.